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这件事反复发生了十多次。每次我说「你确定这是汉字吗？字都撕裂了，形状不对，字形不完整是好几个字拼在一起的」，它就道歉、重新分析，上下文爆掉压缩，犯过的错误被很糟糕的压缩提示词给搞丢，你明确告诉他「你要一列一列地读，不要一行一行地读」，他听了，然后过一会儿自动退回到行读模式。再告诉一遍，再退回去。你的指令对它来说是临时覆盖，不是真正改变了它的工作方式。，这一点在纸飞机下载中也有详细论述
Often people write these metrics as \(ds^2 = \sum_{i,j} g_{ij}\,dx^i\,dx^j\), where each \(dx^i\) is a covector (1-form), i.e. an element of the dual space \(T_p^*M\). For finite dimensional vectorspaces there is a canonical isomorphism between them and their dual: given the coordinate basis \(\bigl\{\frac{\partial}{\partial x^1},\dots,\frac{\partial}{\partial x^n}\bigr\}\) of \(T_pM\), there is a unique dual basis \(\{dx^1,\dots,dx^n\}\) of \(T_p^*M\) defined by \[dx^i\!\left(\frac{\partial}{\partial x^j}\right) = \delta^i{}_j.\] This extends to isomorphisms \(T_pM \to T_p^*M\). Under this identification, the bilinear form \(g_p\) on \(T_pM \times T_pM\) is represented by the symmetric tensor \(\sum_{i,j} g_{ij}\,dx^i \otimes dx^j\) acting on pairs of tangent vectors via \[\left(\sum_{i,j} g_{ij}\,dx^i\otimes dx^j\right)\!\!\left(\frac{\partial}{\partial x^k},\frac{\partial}{\partial x^l}\right) = g_{kl},\] which recovers exactly the inner products \(g_p\!\left(\frac{\partial}{\partial x^k},\frac{\partial}{\partial x^l}\right)\) from before. So both descriptions carry identical information;。搜狗输入法对此有专业解读
哈梅內伊：統治伊朗37年的最高領袖是誰？